Django提供了翻頁器。用Django的Paginator類實現

ApiTest/apiviews.py

每行都加了注釋，希望有助于理解。

from django.shortcuts import renderfrom ApiTest.models import ApiTestfrom django.contrib.auth.decorators import login_requiredfrom django.core.paginator import Paginator, EmptyPage, PageNotAnInteger, InvalidPage@login_requireddef api_test_manage(request): username = request.session.get(’user’, ’’) # 獲取所有接口測試數據 apitest_list = ApiTest.objects.all().order_by(’id’) # 生成Paginator對象對數據分頁，每頁顯示10條數據 paginator = Paginator(apitest_list,10) # 使用request.GET.get()函數獲取url中的page參數的數值。默認第1頁 page = request.GET.get(’page’, 1) # 把獲取的當前頁碼數轉換成整數類型 current_page = int(page) try: # 獲取查詢頁數的接口數據列表，page()函數會判斷page實參是否是有效數字。page()函數源碼附在文章的最后apitest_list = paginator.page(page) except PageNotAnInteger:apitest_list = paginator.page(1) except (EmptyPage, InvalidPage): # paginator.num_pagesapitest_list = paginator.page(paginator.num_pages) return render(request, 'apitest_manage.html', {’user’: username, ’apitests’: apitest_list})二、將views的數據渲染到前端模板上

在對應的html文件中加入此段代碼即可。

<div class='container'> <ul id='pager'>{# 上一頁鏈接 #}{% if apitests.has_previous %}<li class='previous'><a href='http://m.propowerdrill.cn/apitest_manage/?page={{ apitests.previous_page_number }}' rel='external nofollow' >上一頁</a></li>{% else %}<li class='previous disabled'><a href='http://m.propowerdrill.cn/bcjs/17009.html#' rel='external nofollow' rel='external nofollow' >上一頁</a></li>{% endif %}{# 中間數字顯示 #}{% for num in apitests.paginator.page_range %} {% if num == currentPage %}<li class='item active'><a href='http://m.propowerdrill.cn/apitest_manage/?page={{ num }}' rel='external nofollow' rel='external nofollow' >{{ num }}</a></li> {% else %}<li class='item'><a href='http://m.propowerdrill.cn/apitest_manage/?page={{ num }}' rel='external nofollow' rel='external nofollow' >{{ num }}</a></li> {% endif %}{% endfor %}{# 下一頁鏈接 #}{% if apitests.has_next %} {# 如果有下一頁，則正常顯示下一頁鏈接 #} <li class='next'><a href='http://m.propowerdrill.cn/apitest_manage/?page={{ apitests.next_page_number }}' rel='external nofollow' >下一頁</a></li>{% else %} <li class='next disabled'><a href='http://m.propowerdrill.cn/bcjs/17009.html#' rel='external nofollow' rel='external nofollow' >下一頁</a></li>{% endif %} </ul></div>三、效果展示

此類主要用在views文件

class Paginator: def __init__(self, object_list, per_page, orphans=0, allow_empty_first_page=True):self.object_list = object_listself._check_object_list_is_ordered()self.per_page = int(per_page)self.orphans = int(orphans)self.allow_empty_first_page = allow_empty_first_page def validate_number(self, number):'''Validate the given 1-based page number.'''try: if isinstance(number, float) and not number.is_integer():raise ValueError number = int(number)except (TypeError, ValueError): raise PageNotAnInteger(_(’That page number is not an integer’))if number < 1: raise EmptyPage(_(’That page number is less than 1’))if number > self.num_pages: if number == 1 and self.allow_empty_first_page:pass else:raise EmptyPage(_(’That page contains no results’))return number def get_page(self, number):'''Return a valid page, even if the page argument isn’t a number or isn’tin range.'''try: number = self.validate_number(number)except PageNotAnInteger: number = 1except EmptyPage: number = self.num_pagesreturn self.page(number) def page(self, number):'''Return a Page object for the given 1-based page number.'''number = self.validate_number(number)bottom = (number - 1) * self.per_pagetop = bottom + self.per_pageif top + self.orphans >= self.count: top = self.countreturn self._get_page(self.object_list[bottom:top], number, self) def _get_page(self, *args, **kwargs):'''Return an instance of a single page.This hook can be used by subclasses to use an alternative to thestandard :cls:`Page` object.'''return Page(*args, **kwargs) @cached_property def count(self):'''Return the total number of objects, across all pages.'''c = getattr(self.object_list, ’count’, None)if callable(c) and not inspect.isbuiltin(c) and method_has_no_args(c): return c()return len(self.object_list) @cached_property def num_pages(self):'''Return the total number of pages.'''if self.count == 0 and not self.allow_empty_first_page: return 0hits = max(1, self.count - self.orphans)return ceil(hits / self.per_page) @property def page_range(self):'''Return a 1-based range of pages for iterating through withina template for loop.'''return range(1, self.num_pages + 1) def _check_object_list_is_ordered(self):'''Warn if self.object_list is unordered (typically a QuerySet).'''ordered = getattr(self.object_list, ’ordered’, None)if ordered is not None and not ordered: obj_list_repr = (’{} {}’.format(self.object_list.model, self.object_list.__class__.__name__)if hasattr(self.object_list, ’model’)else ’{!r}’.format(self.object_list) ) warnings.warn(’Pagination may yield inconsistent results with an unordered ’’object_list: {}.’.format(obj_list_repr),UnorderedObjectListWarning,stacklevel=3 )五、Page類源碼

此類主要用在html文件

class Page(collections.abc.Sequence): def __init__(self, object_list, number, paginator):self.object_list = object_listself.number = numberself.paginator = paginator def __repr__(self):return ’<Page %s of %s>’ % (self.number, self.paginator.num_pages) def __len__(self):return len(self.object_list) def __getitem__(self, index):if not isinstance(index, (int, slice)): raise TypeError(’Page indices must be integers or slices, not %s.’% type(index).__name__ )# The object_list is converted to a list so that if it was a QuerySet# it won’t be a database hit per __getitem__.if not isinstance(self.object_list, list): self.object_list = list(self.object_list)return self.object_list[index] def has_next(self):return self.number < self.paginator.num_pages def has_previous(self):return self.number > 1 def has_other_pages(self):return self.has_previous() or self.has_next() def next_page_number(self):return self.paginator.validate_number(self.number + 1) def previous_page_number(self):return self.paginator.validate_number(self.number - 1) def start_index(self):'''Return the 1-based index of the first object on this page,relative to total objects in the paginator.'''# Special case, return zero if no items.if self.paginator.count == 0: return 0return (self.paginator.per_page * (self.number - 1)) + 1 def end_index(self):'''Return the 1-based index of the last object on this page,relative to total objects found (hits).'''# Special case for the last page because there can be orphans.if self.number == self.paginator.num_pages: return self.paginator.countreturn self.number * self.paginator.per_page

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